A box is given a push so that it slides across the floor. How far will it go, given that the coefficient of kinetic friction is 0.24 and the push imparts an initial speed of 4.2 m/s?

Answer 1

It will travel a distance X such that:
Work done against friction = Initial kinetic energy

Uk*M*g*X = (1/2)MVo^2
X = Vo^2/(2*Uk*g*)

Uk is the kinetic friction coefficient.

Note that the mass M cancels out.