M*g = 13 * 9.8 = 127.4 N. = Wt. of box =
Normal force(Fn).
Fap-Fs = M*a
47 - Fs = M*0 = 0
Fs = 47 N. = Force of static friction.
us = Fs/Fn = 47/127.4 = 0.369
A box has mass 13 kg and is at rest on a flat floor. A minimum force of 47 N is needed to push the box so it moves across the floor. What is the coefficient of static friction between the box and floor?
1 answer
1 answer