Assuming your typo should say
.... 3 white, 2 red
prob(one red and 1 white) = C(2,1)*C(3,1) / C(5,2) = 6/10 = 3/5
or
could be RW or WR ===> (2/5)(3/4) + 3/5(2/4) = 3/5
prob(two of same ) ====> RR or WW
= C(3,2)/C(5,2) + C(2,2)/C(5,2)
= 3/10 + 1/10 = 2/5
prob(no white) ===> both red = C(2,2)/C(5,2) = 1/10
do the last the same way
A box contains three whole, two red balls, if two balls are selected at random find the probability that
a) one red and one white ball are selected
b) two of the same color is selected
c) no white balls are selected
d) no read balls are selected
3 answers
answer
RESPONCE