a box contains 3 red balls 4 white balls and 9 black balls. two balls are drawn at random from the box with replacement of the first before the second is drawn. what is the probability of getting a red ball on the first draw and a white ball on the second

Answer 1

The probability of drawing a red ball on the first draw is 3/16 (since there are 3 red balls out of a total of 16 balls).

Since the first ball is replaced before the second draw, the probability of drawing a white ball on the second draw is still 4/16.

To find the probability of both events happening, we multiply the probabilities together: (3/16) * (4/16) = 12/256.

Simplifying, we get 3/64.

Therefore, the probability of drawing a red ball on the first draw and a white ball on the second draw is 3/64.