Asked by Travis

A bag contains 5 red balls, 4 white balls, and 3 black balls. Two balls are drawn without
replacement. What is the probability that at least one ball drawn is white?
Answered by Steve
well, what is the probability that <u>no</u> white ball is drawn?
Answered by Travis
I think 8/12 * 7/11= 56/132=42%?
Answered by Steve
right. So what you want is 1 minus that.
Answered by Travis
So 1-.42= .58, so the probability of getting atleast 1 white ball is 58%?
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