mass of ball = 71.2/9.81 = 7.26 kg
Acentripetal = v^2/R = 16/3.6 up
Force in rope = T up
force of gravity down = m g = 71.2 N
acceleration up = 16/3.6
F = m a
T -71.2 = 16/3.6
T = 71.2 + 16/3.6
A bowling ball weighing 71.2 N is attached to the ceiling by a 3.60 m rope. The ball is pulled to one side and released; it then swings back and forth like a pendulum. As the rope swings through its lowest point, the speed of the bowling ball is measured at 4.00 m/s. At that instant, find the magnitude of the acceleration of the bowling ball. At that instant, find the tension in the rope.
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Student itt tech
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