Asked by Sarah
A bowling ball weighing 71.2 N is attached to the ceiling by a 3.80 m rope. The ball is pulled to one side and released; it then swings back and forth like a pedulum. as the rope swings through its lowest point, the speed of the bowling ball is measured at 4.20 m/s. At that instant, find a) the magnitude and direction of the acceleration of the bowling ball and b) the tension in the rope.
Answers
Answered by
drwls
a) The magnitude of the acceleration is V^2/R and it is directed along the rope (i.e. vertical), perpendicular to the direction of motion.
b) If the rope tension is T, Newton's Second Law tells you that
F = T - Mg = Ma = M V^2/R
Solve for T
T = M*(g + V*2/R)
R is the rope length.
b) If the rope tension is T, Newton's Second Law tells you that
F = T - Mg = Ma = M V^2/R
Solve for T
T = M*(g + V*2/R)
R is the rope length.
Answered by
Sarah
So for a I got 17.64 / 3.80 = 4.64 sec is this correct
and then for b i got 71.2( 9.8+ 4.20)*2 / 3.80 and got 524.63
and then for b i got 71.2( 9.8+ 4.20)*2 / 3.80 and got 524.63
Answered by
Anonymous
hell naw
Answered by
Anonymous
LMBO!!!
Answered by
Sailas
thanks
Answered by
Kambua Ombo BEME1
Since it's a pendulum, we we'll use the formula for circular acceleration.
Therefore; a=v^/r
a=v^2/r
=(4.2)^2/3.8
=4.64m/s^2
Since the circular acceleration is always directed to the center so the acceleration of the bowling ball is directed to the center.
b) To find the tension, first we have to find the mass using F=ma.
F=ma
71.2=m(9.81)
m=7.23kg
We cannot use the acceleration to be 9.81, instead we'll use (9.81- 4.64)
Tension=Force=ma=(7.23)(9.81- 4.64)=37.5N
Therefore; a=v^/r
a=v^2/r
=(4.2)^2/3.8
=4.64m/s^2
Since the circular acceleration is always directed to the center so the acceleration of the bowling ball is directed to the center.
b) To find the tension, first we have to find the mass using F=ma.
F=ma
71.2=m(9.81)
m=7.23kg
We cannot use the acceleration to be 9.81, instead we'll use (9.81- 4.64)
Tension=Force=ma=(7.23)(9.81- 4.64)=37.5N
Answered by
Kambua Ombo Gamba
Since it's a pendulum, we we'll use the formula for circular acceleration.
Therefore; a=v^/r
a=v^2/r
=(4.2)^2/3.8
=4.64m/s^2
Since the circular acceleration is always directed to the center so the acceleration of the bowling ball is directed to the center.
b) To find the tension, first we have to find the mass using F=ma.
F=ma
71.2=m(9.81)
m=7.23kg
We cannot use the acceleration to be 9.81, instead we'll use (9.81- 4.64)
Weight of the swinging pendulum=Force=ma=(7.23)(9.81- 4.64)=37.5N
*Now we’ll use Newton’s second law;
T-mg=ma
T-(7.23)(9.81)=(7.23)(9.81-4.46)
T-71.2=(7.23)(5.17)
T-71.2=37.5
T=37.5+71.2
T=108.7N
Therefore; a=v^/r
a=v^2/r
=(4.2)^2/3.8
=4.64m/s^2
Since the circular acceleration is always directed to the center so the acceleration of the bowling ball is directed to the center.
b) To find the tension, first we have to find the mass using F=ma.
F=ma
71.2=m(9.81)
m=7.23kg
We cannot use the acceleration to be 9.81, instead we'll use (9.81- 4.64)
Weight of the swinging pendulum=Force=ma=(7.23)(9.81- 4.64)=37.5N
*Now we’ll use Newton’s second law;
T-mg=ma
T-(7.23)(9.81)=(7.23)(9.81-4.46)
T-71.2=(7.23)(5.17)
T-71.2=37.5
T=37.5+71.2
T=108.7N
Answered by
Kambua Ombo Gamba
There's two of my answers above so chose whichever you prefer
Answered by
Bread
Bread
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