A body weigh of 0.26N in air. When total emmers in water weight 0.16h and 0.18n in another liquid. Calculate the relative density of of liquid

Answer 1

what is its volume v?
rho g v = force up from water = 1000 kg/m^3 * 9.81 * v
that is the change in weight from air to water
9810 v = .26 - .16 = .1 n
so
v = .1 / 9810 meters^3
now
rho g V = .26 - .18 = .08
rho *9.81 * .1/9810 = .08
rho = .8 (9810/9.81)
but it asked for "relative" density so we want rho/water density = rho/1000
well that is 0.8