a body of mass 5 kg is thrown vertically upwards with a speed of 10m/s what is its k.e. when it is thrown find its potential energy when it reaches at highest poiint also find maximum height attained by the body?

Answer 1

a. KE = 0.5m*Vo = 2.5*(10)^2 = 250 Joules

b. hmax = (Vf^2-Vo^2)/2g.
hmax = (0-(10)^2 / -19.6 = 5.10 m.

c. PE = mg*h = 5 * 9.8 * 5.1=250 Joules

Answer 2

m=5kg
V=10m/s
K.E=1/2mv^2
P.E=mgh
K.E=P.E
K.E=1/2mv^2
=1/2x10x5x5
=125
P.E=125
Mgh =P.E
5x10xh=125
10h=125/5=25
h=25/10=2.5 answer