A body of mass 2kg is released from rest and falls

freely under gravity. Find its speed when it has
fallen a distance of 10m.

1 answer

To find the speed of the body when it has fallen a distance of 10m, we can use the equation for gravitational potential energy:

Potential energy (PE) = mgh

Where:
m = mass of the body (2kg)
g = acceleration due to gravity (9.8 m/s^2)
h = height fallen (10m)

Since the body is released from rest, all its initial potential energy is converted into kinetic energy as it falls:

PE = KE

Therefore, we can set up the equation:

mgh = (1/2)mv^2

Where:
v = speed of the body

Simplifying the equation:

2 * 9.8 * 10 = (1/2) * 2 * v^2

196 = v^2

Taking the square root of both sides:

v = √196

v = 14 m/s

Therefore, the speed of the body when it has fallen a distance of 10m is 14 m/s.