A body of mass 2 kg is dropped from the top of a tower of height 100m. If the acceleration due to gravity is 10 m/s2 calculate the K.E at the end of 5 seconds

Answer 1

Note that the body will hit the ground after 4.47 s. The KE after 5 seconds will depend how well it bounces.

trick question.

Answer 2

2500j

Answer 3

v=u+gt
V= 0 + 10*5
V= 50
K.E= 1/2 *2*50*50
K.E = 2500J