a = F/m = 20/10 = 2 m/s^2
d = (1/2) a t^2 = (1/2)(1) (3*3) = 9 meters
work done = force * distance = 10 * 9 = 90 Joules
gain in kinetic energy = work done
A body of mass 10kg is acted on by a constant force of 20n for 3 second calculate the kinetic energy at the end of the time
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