To calculate the potential and kinetic energy of the body when it is at a height of 2m from the ground, we need to consider the conservation of mechanical energy.
The potential energy of an object is given by the formula PE = mgh, where m is the mass, g is the acceleration due to gravity (9.8 m/s^2), and h is the height.
The kinetic energy of an object is given by the formula KE = 1/2mv^2, where m is the mass and v is the velocity.
Initially, when the body is at a height of 3m from the ground, the potential energy is:
PE = mgh = 0.5 kg * 9.8 m/s^2 * 3m = 14.7 Joules.
The body is then released and falls to a height of 2m from the ground.
The change in potential energy can be calculated as:
ΔPE = mgh2 - mgh1 = 0.5 kg * 9.8 m/s^2 * (2m - 3m)
ΔPE = -4.9 Joules.
The change in potential energy is negative because the body is losing potential energy as it falls.
Assuming no energy is lost due to air resistance or other non-conservative forces, the change in potential energy must be equal to the change in kinetic energy.
Therefore, the kinetic energy when the body is at a height of 2m from the ground is:
KE = ΔPE = -4.9 Joules.
Note that the negative sign indicates that the kinetic energy is negative, meaning the body is moving in the downward direction.
A body of mass 0.5 kg released from a height of 3mcalculate potential and kinetic energy when it is at a height of 2m from the ground
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