At what height above the ground must a body of mass 10kg be situated in order to have a potential energy equal in value to the kinetic energy passed by another body of mass 10kg moving with a velocity of 10ms-1(g=9.8ms-2).
2 answers
Bro don't even bother asking for help in here. They won't even try and help you and give you a attitude like "Dr.Bob"
Can it, @Josh.
PE = mgh
KE = 1/2 mv^2
so, just solve
10*9.81*h = 1/2 * 10 * 10^2
and that's "possessed," not "passed."
PE = mgh
KE = 1/2 mv^2
so, just solve
10*9.81*h = 1/2 * 10 * 10^2
and that's "possessed," not "passed."