A body is thrown height vertically upward with initial velocity 9.8 m/s it will attain height?

Answer 1

The height the body will attain can be determined using the kinematic equation:

h = (v^2 - u^2) / (2a)

where:
h = height attained by the body
v = final velocity (0 m/s when it reaches its highest point)
u = initial velocity (9.8 m/s)
a = acceleration due to gravity (-9.8 m/s^2)

Plugging in the values, we get:

h = (0^2 - 9.8^2) / (2*(-9.8))
h = (-96.04) / (-19.6)
h = 4.898 meters

Therefore, the body will attain a height of approximately 4.898 meters before it starts falling back down.