a body is released from a height and falls freely towards the earth. exactly one sec later another body is released.what is the distance between the two bodies 2sec after the release of the second body. if g=9.8m/s^2.

Answer 1

hf1 is the final height of first
hf2 is the final height of second.

so,the question is

hf1-hf2=ho1-4.9t^2-ho2+4.9(t-1)^2

t=2; ho1=ho2