A block (weight= 10kg) is sitting on a surface with friction (coefficient= 0.5). A force (push) is applied to the end of the block, 35 degrees below the horizontal. Calculate the magnitude of the force to move the block.

Answer 1

y: N=mg+F•sinα
x: F•cosα=F(fr) =μ•N=μ•( mg+F•sinα)
F=μ•m•g/(cosα-μ•sinα)