A block starts with a speed of 18.0 m/s and slides for a distance of 2.2 m down a 40° ramp (muk = 0.43). What is its final speed? (m/s)

Question

Thanks for suggeting the following solution.
The block starts with an initial speed of 18.0 m/s.Does it have any effect?

Final KE = PE loss - (work done against friction)
(1/2)M V^2 = M g L sin40 - M g L cos40*0.43
L = 2.2 m. Cancel out the M's and solve for V^2.

Answer 1

Yes, the approach suggested should have had the initial kinetic energy on the right side of the equation.

I recall providing the original answer and apologize for my error. I'm glad you caught it.

Answer 2

Thank you very much.