A. Work = F*cosA * d = 43 J.
60*cosA * 2.0 = 43
120*cosA = 43
cosA = 0.35833
A = 69o
B. a = (V^2-Vo^2)/2d
a = (2.7^2-0)/4 = 1.82 m/s^2.
F*cos69 = m*a
60*cos69 = m*1.82
m = 60*cos69/1.82 = 11.80 kg.
A block rests on a horizontal frictionless surface. A string is attached to the block, and is pulled with a force of 60.0 N at an angle θ above the horizontal. After the block is pulled through a distance of 2.00 m, its speed is 2.70 m/s, and 43.0 J of work has been done on it.
A)What is the angle θ?
B)Calculate the mass of the block.
1 answer
1 answer