Work
W=F•s•cosθ
cosθ= W/F•s= 43/60•2=0.358
θ=69°
ma=Fcos θ
a=v²/2s= 2.7²/2•2 = 1.82 m/s²
m= Fcos θ/a=60•0.358/1.82 =11.8 kg
A)A block rests on a horizontal frictionless surface. A string is attached to the block, and is pulled with a force of 60.0 N at an angle θ above the horizontal. After the block is pulled through a distance of 2.00 m, its speed is 2.70 m/s, and 43.0 J of work has been done on it. What is the angle θ?
B)Calculate the mass of the block.
1 answer
1 answer