1. W = Change in KE = 0.5M*Vo^2 = 0.5*6*4.1^2 = 50.4 J.
Ff = M*a.
-7.1 = 6*a.
a = -1.18 m/s^2.
2. V^2 = Vo^2 + 2a*d = 0.
4.1^2 + (-2.36)d = 0,
d =
A block of mass 6 kg, which has an initial
velocity of 4.1 m/s at time t = 0, slides on a
horizontal surface.
Calculate the work that must be done on
the block to bring it to rest.
Answer in units of J.
If a constant friction force of 7.1 Newtons is
exerted on the block by the surface, what is
the acceleration?
Answer in units of m/s
2
Determine the distance that the block slides
as it comes to rest.
Answer in units of m.
1 answer