A block is released from the top of a frictionless incline plane as pictured above. If the total distance travelled by the block is 1.2 m to get to the bottom, calculate how fast it is moving at the bottom using Conservation of Energy.(incline 20 degrees mass of block is 2.5kg)

Answer 1

the vertical height traveled is 1.2 sin20°

PE lost is KE gained, so

mgh = 1/2 mv^2
gh = 1/2 v^2
you have g and h, so get v.

Answer 2

2.83