A block is given an initial velocity of 7.00 m/s up a frictionless 19.0° incline. How far up the incline does the block slide before coming (momentarily) to rest?

Answer 1

It will rise a vertical distance H until the potential energy increase MgH equals the initial kinetic energy,
(1/2) M V^2

Threfore H = V^2/(2 g)

The distance X that it moves up the incline is given by
sin 19 = H/X