A block is given an initial velocity of 5.00 m/s up a frictionless 20degree incline. How far up the incline does the block slide before coming to rest?

5 answers

here
vf =0
vo = 5m/s
a=g.sin(theta)
theta=20 degree
g=-9.8 m/s^2
s=?
use

s= [vf^2 - vo^2]/2a

Ans=1.4 m
Hey there, I did the same question but I got 3.78m as my final answer. I used the same calculation and values that you did too.
Yes my answer is also 3.73
The solution is correct but he/she used radians instead of degrees
If you got 3.78, chances are you dropped the 2 in the denominator. 2a, not just a. 1.4 is correct.