A bit flower vase has a 5 begonias, 6 carnations and 7 tulips. Two flowers are randomly selected without replacement. What is the probability of selecting two carnations? Express in simplest form of fractions.

Answer 1

There are a total of 5 + 6 + 7 = 18 flowers in the vase.

The probability of selecting a carnation on the first draw is 6/18, or 1/3.

Since we are drawing without replacement, there will be 5 + 7 = 12 flowers left in the vase for the second draw.

The probability of selecting another carnation on the second draw, given that the first draw was a carnation, is 5/12.

To find the probability of both events occurring, we multiply the probabilities:

P(selecting 2 carnations) = (1/3) x (5/12) = 5/36

Therefore, the probability of selecting two carnations is 5/36.