We can analyze the horizontal and vertical components of the rock's motion separately.
Given that the bird was flying horizontally at 4.25 m/s, the horizontal velocity of the rock when it was dropped is also 4.25 m/s.
Let's focus on the vertical component of motion. The vertical velocity of the rock when it was dropped is 0 m/s because it was moving horizontally. The final vertical velocity of the rock is given as -13.0 m/s (negative because it is moving downwards).
Using the kinematic equation, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time elapsed, we can find the time elapsed for the vertical motion.
Final vertical velocity (v) = initial vertical velocity (u) + acceleration (a) * time (t)
-13.0 m/s = 0 m/s + (-9.8 m/s^2) * t
Solving for t:
-13.0 m/s = -9.8 m/s^2 * t
t = -13.0 m/s / -9.8 m/s^2
t ≈ 1.33 s
Since the rock was originally moving with the bird, the time elapsed for the rock is the same as the time elapsed for the bird. Therefore, approximately 1.33 seconds have passed.
A bird flying horizontally at 4.25 m/s
accidentally drops a rock it was carrying. A short time later, the rock's velocity is 13.0 m/s at -70.9°.
How much time has passed?
(Unit = s)
(Hint: the rock was originally moving with the bird.)
1 answer
1 answer