A bird flying horizontally at 4.25 m/s

accidentally drops a rock it was carrying. A short time later, the rock's velocity is 13.0 m/s at -70.9°.
How much time has passed?

1 answer

To find the time that has passed, we can use the fact that the acceleration due to gravity is 9.8 m/s².

First, we need to find the horizontal and vertical components of the rock's velocity when it was dropped.
The bird was flying horizontally, so the horizontal component of the rock's velocity remains the same, which is 4.25 m/s.

Next, we can use the vertical component of the rock's velocity to find the time it took to reach that velocity.
The vertical component of the velocity is given as -70.9° at a magnitude of 13.0 m/s, so we can use trigonometry to find the vertical component of the velocity:
Vertical component = 13.0 m/s * sin(-70.9°) = -12.493 m/s (Negative because it is downward direction)

The relationship between time, initial velocity, acceleration, and final velocity is given by the equation:
Final velocity = Initial velocity + (acceleration * time)

Using the vertical component of velocity:
-12.493 m/s = 0 m/s + (-9.8 m/s²) * time

Solving for time:
time = -12.493 m/s / (-9.8 m/s²)
time ≈ 1.27 s

Therefore, approximately 1.27 seconds have passed since the rock was dropped.
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