A bicyclist traveling at 7 m/s rides around an unbanked curve. The coefficient of friction between the tires and the road is 0.38. What is the radius of the shortest turn that the bicyclist can safely make?
2 answers
Can someone please respond on this one.
Fc = mvˆ2/radius
Friction = mg*(coefficient of friction)
So, mvˆ2/r = mg0.38
masses cancel out
vˆ2/r=g0.38
r= vˆ2/g0.38
r= 7ˆ2/9.81*0.38 = 13.144482 m
Friction = mg*(coefficient of friction)
So, mvˆ2/r = mg0.38
masses cancel out
vˆ2/r=g0.38
r= vˆ2/g0.38
r= 7ˆ2/9.81*0.38 = 13.144482 m
3 answers