10 s. = 10,000 mS.
x = t/RC, Vr = 9/e^x = 9-8 = 1,
e^x = 9, X = 2.197 = 10,000/(R*47), 2.197 =213/R, 2.197R = 213, R = 96.8Kohms.
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A battery of 9 V charges a capacitor of 47 ìF through a resistor.
What resistor value needs to be used to obtain a voltage across the
capacitor of 8 V when 10 seconds have elapsed ? You will need to
obtain the standard equation for the voltage across the capacitor
charging in this circuit configuration.
I have done the first part of the question but I'm not sure if that's the correct answer.
1 answer