A battery has an unknown e.m.f, ε,and an internal resistance r = 0.40Ω. When a resistance R = 5.60Ω is connected across the terminals of the battery, the terminal potential difference across the battery is 11.2V. What is the e.m.f. of the battery?

Answer 1

Hey , try yourself this time and Henry or I or someone will check.

Answer 2

I = V/R = 11.2/5.6 = 2A.
e.m.f. = I * (r+R) = 2 * (0.4+5.6) =