i = V/R = 12 / .004 amps
P = i V = 144/R Joules
i = 80
R = V/i = 12/ 80
external resistance Rx = R - .004
power to motor = i^2 Rx = 6400 Rx
A 12-V automobile storage battery has an internal resistance of 0.004 ohms. A) Find the current and power dissipation when the terminals are connected by a conductor of negligible Resistance B) The battery delivers 80A to the starter motor. What resistance would draw the same current? C) How much power is supplied to the motor?
1 answer