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A battery delivering a current of 55.0 A to a circuit has a terminal voltage of 21.8 V. The electric power being dissipated by the internal resistance of the battery is 36 W. Find the emf of the battery.

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Vi * I = 36 W.
Vi * 55 = 36
Vi = 0.655 V0lts. = Internal voltage drop.

E = 21.8 + 0.655 = 22.5 V. = emf of battery.

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