The volts across your load resistor = 11.2V
Power delivered = 26.0 W
Power = Volts x Amps so Current (Amps) = 26.0/11.2 V = 2.32A
(A) 11.2V/2.32A = 4.83 ohm
Volts lost across internal resistance = 15 - 11.2 = 3.8V
Internal resistance = Lost Volts/Current = 3.8/2.32 = 1.64 ohms (B)
A battery has an emf of 15.0 V. The terminal voltage of the battery is 11.2 V when it is delivering 26.0 W of power to an external load resistor R.
(a) What is the value of R?
(b) What is the internal resistance of the battery?
1 answer
1 answer