A basketball player shoots the ball with an initial velocity of 14.4 ft./sec. at an angle of 41.9° with the horizontal. To the nearest tenth, find the initial horizontal component of the vector that represents the velocity of the ball.
(1 point)
Responses
4.8 ft./sec.
4.8 ft./sec.
5.4 ft./sec.
5.4 ft./sec.
9.6 ft./sec.
9.6 ft./sec.
10.7 ft./sec.
3 answers
9.6 ft./sec.
14.4 * cos (41.9 degrees) = 14.4 * 0.7443 = 10.7
I think you found the vertical, not the horizontal
I think you found the vertical, not the horizontal
You are correct, I apologize for the mistake. The initial horizontal component of the velocity is 10.7 ft./sec. Thank you for pointing that out.