A 2.12 m tall basketball player wants to sink the ball into a basket located 14 m from the player, as in Figure P3.58. If he shoots the ball at a 46° angle, at what initial speed must he throw the basketball so that it goes through the hoop without striking the backboard?

Answer 1

Vo^2*sin(2A)/g = 14 m.
Vo^2*sin(92)/9.8 = 14
0.10198*Vo^2 = 14
Vo^2 = 137.3
Vo = 11.72 m/s.

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