What is the distance from halfcourt to the basket?
horizontal distance= V*cosTheta*time
Vertical distance=0=VsinTheta*time-4.9*t^2
in the second equation...
0=V*sinTheta-4.9t
solve for t in terms of V
then put that into the horizontal equaion, and solve for V
a basketball player is trying to make a half-court ump shot and releases the ball at the height of the basket. assuming that the ball is launched at 51 degrees, 14 m from the basket, what speed must the player give the ball?
1 answer