A basketball player shoots a free throw at a 50 degree angle. Assume the ball is released at a height of 1.8 meters, the hoop is 3 meters off of the floor and 4.6 meters away from the shooter. With what velocity should the player release the ball to hit nothing but net?
I have gotten to this point but I am unaware of how to calculate the last part:
4.6 = (x cos 50) t so t = 4.6/(x cos 50)
3 = 1.8 + (x sin 50) t - 4.9 t^2
1.2 = (x sin 50)(4.6/x cos 50) - 4.9 (4.6^2)/(x^2 cos^2 50)
1.2 = 4.6 tan 50 - 4.9 (4.6^2)/(x^2 cos^2 50)
2 answers