To analyze the quadratic function \( f(x) = -(x + 1.4)^2 + 6 \), we can break down the two parts you've mentioned.
Part A: Identify the vertex
The vertex form of a quadratic function is given by \( f(x) = a(x - h)^2 + k \), where \((h, k)\) is the vertex of the parabola. In this case, the function is given as:
\[ f(x) = -(x + 1.4)^2 + 6 \]
We can rewrite this in vertex form:
- The vertex is found directly from the expression \( -(x + 1.4)^2 + 6 \).
- Here, \( h = -1.4 \) and \( k = 6 \).
Thus, the vertex is:
\[ \text{Vertex} = (-1.4, 6) \]
Part B: Complete the table
Now we'll calculate \( f(x) \) for the given values \( x = 0, 1, 2, \) and \( 3 \).
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\( x = 0 \): \[ f(0) = -((0) + 1.4)^2 + 6 = -(1.4)^2 + 6 = -1.96 + 6 = 4.04 \]
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\( x = 1 \): \[ f(1) = -((1) + 1.4)^2 + 6 = -(2.4)^2 + 6 = -5.76 + 6 = 0.24 \]
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\( x = 2 \): \[ f(2) = -((2) + 1.4)^2 + 6 = -(3.4)^2 + 6 = -11.56 + 6 = -5.56 \]
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\( x = 3 \): \[ f(3) = -((3) + 1.4)^2 + 6 = -(4.4)^2 + 6 = -19.36 + 6 = -13.36 \]
Now, we can summarize these results in the table:
| x | f(x) | |-----|----------| | 0 | 4.04 | | 1 | 0.24 | | 2 | -5.56 | | 3 | -13.36 |
Summary of Answers:
- Part A: Vertex = \( (-1.4, 6) \)
- Part B:
| x | f(x) | |-----|----------| | 0 | 4.04 | | 1 | 0.24 | | 2 | -5.56 | | 3 | -13.36 |