The total number of fruits in the basket is 5 + 3 = 8.
The probability of selecting an apple first is 5/8.
After selecting an apple, there are now 4 apples and 3 pears left in the basket. Therefore, the probability of selecting another apple second is 4/7.
Thus, the probability of selecting both fruits as apples is (5/8) * (4/7) = 20/56 = 5/14.
Therefore, the probability that both fruits are apples is 5/14.
A basket of fruits contains 5 apples and 3 pears. Sharon took two fruits at random. What is the probability that both fruits are apples? Write your answer in the simplest form of fraction.
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5 answers
A coin is flipped and a spinner is spun simultaneously. The spinner is divided into six equally sized sections labeled with 1, 2, 3, 4, 5, 6. What is the probability of flipping a tail and landing on 5?
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(1 point)
When flipping a coin, there are 2 equally likely outcomes - heads or tails. The probability of flipping a tail is 1/2.
When spinning the spinner, there are 6 equally likely outcomes - landing on 1, 2, 3, 4, 5, or 6. The probability of landing on 5 is 1/6.
Since the coin flip and spinner spin are happening simultaneously and are independent events (the outcome of one does not affect the other), we can multiply the probabilities:
P(tail and landing on 5) = P(tail) * P(landing on 5) = (1/2) * (1/6) = 1/12
So, the probability of flipping a tail and landing on 5 is 1/12.
When spinning the spinner, there are 6 equally likely outcomes - landing on 1, 2, 3, 4, 5, or 6. The probability of landing on 5 is 1/6.
Since the coin flip and spinner spin are happening simultaneously and are independent events (the outcome of one does not affect the other), we can multiply the probabilities:
P(tail and landing on 5) = P(tail) * P(landing on 5) = (1/2) * (1/6) = 1/12
So, the probability of flipping a tail and landing on 5 is 1/12.
A money envelope contains five $10 bills, ten $20 bills, and fifteen $50 bills. Sandra randomly selects two bills without returning the first bill. What is the probability of getting a $10 bill then a $50 bill? Write your answer in the simplest form of fraction.
(1 point)
(1 point)
The total number of bills in the envelope is 5 + 10 + 15 = 30.
The probability of picking a $10 bill first is 5/30 = 1/6.
After selecting a $10 bill, there are now 4 $10 bills, 10 $20 bills, and 15 $50 bills left in the envelope. The total number of bills remaining is 4 + 10 + 15 = 29.
Therefore, the probability of picking a $50 bill second is 15/29.
Thus, the probability of getting a $10 bill then a $50 bill is (1/6) * (15/29) = 15/174 = 5/58.
Therefore, the probability of getting a $10 bill then a $50 bill is 5/58.
The probability of picking a $10 bill first is 5/30 = 1/6.
After selecting a $10 bill, there are now 4 $10 bills, 10 $20 bills, and 15 $50 bills left in the envelope. The total number of bills remaining is 4 + 10 + 15 = 29.
Therefore, the probability of picking a $50 bill second is 15/29.
Thus, the probability of getting a $10 bill then a $50 bill is (1/6) * (15/29) = 15/174 = 5/58.
Therefore, the probability of getting a $10 bill then a $50 bill is 5/58.
6 answers