There are a total of 8 fruits in the basket, and 5 of them are apples.
The probability of selecting an apple on the first draw is 5/8.
After the first apple is drawn, there are 4 apples and 3 pears left in the basket, so the probability of selecting another apple on the second draw is 4/7.
To find the probability of both events happening, we multiply the probabilities:
P(both are apples) = (5/8) x (4/7) = 20/56
Simplifying this fraction, we get:
P(both are apples) = 5/14
A basket of fruits contains 5 apples and 3 pears. Sharon took two fruits at random. What is the probability that both fruits are apples? Write your answer in the simplest form of fraction.
6 answers
A coin is flipped and a spinner is spun simultaneously. The spinner is divided into six equally sized sections labeled with 1, 2, 3, 4, 5, 6. What is the probability of flipping a tail and landing on 5?
The probability of flipping a tail is 1/2, since there are two equally likely outcomes (heads or tails) and each has a probability of 1/2.
The probability of landing on 5 on the spinner is 1/6, since there are six equally likely outcomes (each labeled with a different number) and only one of them is labeled 5.
To find the probability of both events happening, we multiply the probabilities:
P(tail and 5) = (1/2) x (1/6) = 1/12
So the probability of flipping a tail and landing on 5 is 1/12.
The probability of landing on 5 on the spinner is 1/6, since there are six equally likely outcomes (each labeled with a different number) and only one of them is labeled 5.
To find the probability of both events happening, we multiply the probabilities:
P(tail and 5) = (1/2) x (1/6) = 1/12
So the probability of flipping a tail and landing on 5 is 1/12.
A money envelope contains five $10 bills, ten $20 bills, and fifteen $50 bills. Sandra randomly selects two bills without returning the first bill. What is the probability of getting a $10 bill then a $50 bill? Write your answer in the simplest form of fraction.
The total number of bills is 5 + 10 + 15 = 30.
If Sandra selects a $10 bill first, there will be 4 $10 bills left in the envelope, and a total of 29 bills left.
If Sandra then selects a $50 bill, there will be 15 $50 bills left in the envelope, and a total of 28 bills left.
So the probability of getting a $10 bill then a $50 bill is:
(5/30) x (15/29) = 75/870
Simplifying this fraction, we get:
P($10 then $50) = 15/174
If Sandra selects a $10 bill first, there will be 4 $10 bills left in the envelope, and a total of 29 bills left.
If Sandra then selects a $50 bill, there will be 15 $50 bills left in the envelope, and a total of 28 bills left.
So the probability of getting a $10 bill then a $50 bill is:
(5/30) x (15/29) = 75/870
Simplifying this fraction, we get:
P($10 then $50) = 15/174
ANSWERS FOR THE CHECK ANSWERS ARE...
1. 5/14
2. 1/12
3. 0.075
4. 52%
5. 5/58
Hope this helps :)
1. 5/14
2. 1/12
3. 0.075
4. 52%
5. 5/58
Hope this helps :)