A baseball player hits a line drive. Just before the ball is struck, it is moving east at a speed of 38.8 m/s (87 mi/h). Just after contact with the bat, 1.05 10-3 s later, the ball is moving west at a speed of 46 m/s (103 mi/h). Find the ball's average acceleration.

Answer 1

Δp=p₂-(-p₁) = p₂ + p₁ = m(v₂+v₁),
F= Δp/Δt=ma ,
m(v₂+v₁)/Δt = ma,
a= (v₂+v₁)/Δt=
=(46+38)/1.05•10⁻³=8•10⁴ m/s²

Answer 2

change in velocity / change in time

(38.8 + 46) / .00105