A baseball is thrown upwards from a height of 2 meters with an initial velocity of 10 meters per second. Use the fact that -9.8 meters per second squared is constant acceleration due to gravity to answer the following:

Question

The maximum height of the ball

The time it takes for the ball to hi the ground.

Answer 1

height = -4.9t^2 + 10t + 2
d(height)/dt = -9.8t + 10
= 0 at max height

9.8t = 10
t = 10/9.8

height = -4.9(10/9.8)^2 + 10(10/9.8) + 2 = appr 7.102 m is the max height

when it reaches the ground
0 = -4.9t^2 + 10t + 2
4.9t^2 - 10t- 2 = 0
t = (10 ± √139.2)/9.8 = 1.306 seconds or a negative

check my arithmetic