a. time=distance/velocity=60.5/139 seconds
b. drop= 4.9t^2
c. what is 5.3+.833- drop?
a baseball is thrown from a mound .833ft above ground level ,to home plat 60.5 feet away. the ball is released horizontally from the pitcher with a velocity of 139ft/s when the pitchers hand is 5.3ft above the mound. a)how long will it take to reach home plate? b) how far did the ball drop on the way to home plate and c) what would be the height of the ball above the ground when it reaches home plate?
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