A baseball diamond is actually a square with 90 feet between the bases. The pitcher's mound is 60.5 feet from home plate. How far is the pitcher's mound from the first base?

Question

Round all answers to 1 decimal place

I used the Pythagorean theorem and got 66.6. Is that right?

Answer 1

the diagonal is 90√2=127.28 feet, so the mound is not in the center of the diamond (63.64 ft from home).

So, you can't use the Pythagorean Theorem here. Instead, use the law of cosines:

x^2 = 60.5^2 + 90^2 - 2*60.5*90*cos45°
x = 63.72 feet