A baseball catcher puts on an exhibition by catching a 0.15-kg ball dropped from a helicopter at a height of 101 m. What is the speed of the ball just before it hits the catcher's glove 1.0 m above the ground? (g = 9.8 m/s2 and ignore air resistance)

Answer 1

V = sqrt(2gH)

The mass is irrelevant.
H is the height change, which is 100 m in this case.

Answer 2

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