A balloon rising vertically with a velocity of 5m/s releases an object from a height of 100m.(a)How many seconds after it's release will the object reach the ground?(b)At what velocity will the object reach the ground?

Answer 1

height = -4.9t^2 + 5t + 100
a) you want height = 0
-4.9t^2 + 5t + 100 = 0
4.9t^2 - 5t - 100 = 0
solve for t, reject the negative answer

b) d(height)/dt = -9.8t + 5
sub in your answer from a)

Answer 2

asnakc