A balloonist, riding in the basket of a hot air balloon that is rising vertically with a constant velocity of 9.5 m/s, releases a sandbag when the balloon is 44.3 m above the ground. Neglecting air resistance, what is the bag's speed when it hits the ground? Assume g = 9.80 m/s2.

Answer 1

Set up the formula,

4.9t^2 +9.5 -44.3 use the quadratic formula to get 2.19 for t.

44.3 = 1/2(9.5 +Vf)2.19

= 30.96 m/s