The ball after leaving the table
takes part in two motions: horizontal uniform motion
L = v(hor) •t,
and vertical free fall
H = gt^2/2,
t = sqroot(2H/g) = sqroot(2•1/9.8) = 0.2 s.
L = v(hor) •t = 4.4•0.2=0.88 m.
A ball rolls with a speed of 4.4 m/s toward the edge of a table that is 1 m above the floor. The ball rolls off the table.
a. How long is it in the air? s
b. How far out from the edge of the table does the ball hit the floor? m
2 answers
a ball rolls 5cm in 5 seconds what is the speed of the ball?
0 answers