An orange rolls across a table with a speed of 0.5 m/s and falls off the edge. If it lands 3 m from the edge of the table, from what height does it fall?

Answer 1

d = Vx*Tf = 3 m.
0.5m/s * Tf = 3
Tf = 6 s. = Fall time.

h = 0.5g*Tf^2 = 4.9 * 6^2 = 176.4 m.

Answer 2

An orange rolls across a table with a speed of 0.5 m/s and falls off the edge. If it lands 3 m from the edge of the table, from what height does it fall?

Answer 3

Given:
Vox= 0.5m/s
Dx= 3m
g= 9.8 m/s²

solve for
dy

Formula: dy=voy+ 1/2 gt²
solve for time
dx=vxt
dx/vx=vxt/vx
(cancel both vx)
t=dx/vx
t= 3m/0.5m/s

formula dy=voy + t 1/2gt²

dy=1/2(9.8 m/s²) (6s)²

answer: -176.4 m

Answer 4

A 25-kg boy is riding a 12-kg bike moving at4.5m/s.what is the total momentum of the boy and the bike together