The ball slows down and comes to a stop due to gravity acting against its motion. We can use the kinematic equation to determine the acceleration of the ball.
The kinematic equation is:
v^2 = u^2 + 2as
where:
v = final velocity (0 m/s, since the ball comes to a stop)
u = initial velocity (2.0 m/s)
a = acceleration
s = distance traveled up the slope (2.7 m)
Plugging in the values we have:
0 = (2.0)^2 + 2a(2.7)
0 = 4 + 5.4a
-4 = 5.4a
a = -4/5.4
a = -0.74 m/s^2
Therefore, the acceleration of the ball as it rolls up the slope is -0.74 m/s^2.
a ball rolls 2.7m up a constant slope before it comes to a stop if the initial velocity of the ball was 2.0m/s what is the acceleration of the ball as it rolls
1 answer
1 answer